38x^2-148x-16=0

Solution for 38x^2-148x-16=0 equation:

38x^2-148x-16=0

a = 38; b = -148; c = -16;
Δ = b2-4ac
Δ = -1482-4·38·(-16)
Δ = 24336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{24336}=156$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-148)-156}{2*38}=\frac{-8}{76}
=-2/19
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-148)+156}{2*38}=\frac{304}{76}
=4
$